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Synopsis We solve a well-known job interview puzzle.
Description FizzBuzz
![]() Write a program that prints the numbers from 1 to 100. But for multiples of three print "Fizz" instead of the number and for the multiples of five print "Buzz". For numbers which are multiples of both three and five print "FizzBuzz".Surprisingly, many candidates fail to pass this test. Solutions to FizzBuzz in various languages are available here ![]()
Examples Here are a few possible Rascal solutions:
module demo::basic::FizzBuzz import IO; public void fizzbuzz() { for(int n <- [1 .. 101]){ fb = ((n % 3 == 0) ? "Fizz" : "") + ((n % 5 == 0) ? "Buzz" : ""); println((fb == "") ?"<n>" : fb); } } public void fizzbuzz2() { for (n <- [1..101]) switch(<n % 3 == 0, n % 5 == 0>) { case <true,true> : println("FizzBuzz"); case <true,false> : println("Fizz"); case <false,true> : println("Buzz"); default: println(n); } } public void fizzbuzz3() { for (n <- [1..101]) { if (n % 3 == 0) print("Fizz"); if (n % 5 == 0) print("Buzz"); else if (n % 3 != 0) print(n); println(""); } } rascal>import demo::basic::FizzBuzz; ok rascal>fizzbuzz(); 1 2 Fizz 4 Buzz Fizz 7 8 Fizz Buzz 11 Fizz 13 14 FizzBuzz 16 17 Fizz 19 Buzz Fizz 22 23 Fizz Buzz 26 Fizz 28 29 FizzBuzz 31 32 Fizz 34 Buzz Fizz 37 38 Fizz Buzz 41 Fizz 43 44 FizzBuzz 46 47 Fizz 49 Buzz Fizz 52 53 Fizz Buzz 56 Fizz 58 59 FizzBuzz 61 62 Fizz 64 Buzz Fizz 67 68 Fizz Buzz 71 Fizz 73 74 FizzBuzz 76 77 Fizz 79 Buzz Fizz 82 83 Fizz Buzz 86 Fizz 88 89 FizzBuzz 91 92 Fizz 94 Buzz Fizz 97 98 Fizz Buzz ok ![]() |