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Synopsis Retrieve a slice of a list.
Syntax
  1. Exp1 [ Exp2 .. Exp4]
  2. Exp1 [ Exp2 , Exp3 .. Exp4]
where Exp2 and Exp4 are optional.
Types
Exp1 Exp2 Exp3 Exp4 Exp1 [ Exp2 .. Exp4 ] or Exp1 [ Exp2 , Exp3 .. Exp4]
list[T1] int int int list[T1]
Description List slicing uses the integer values of Exp2 and Exp4 to determine the begin (inclusive) and end (exclusive) of a slice from the list value L of Exp1. Negative indices count from the end of the list backwards. Using the second form, an extra index Exp3 is given that determines the index of the second element in the slice and establishes the step between successive elements in the slice. The default step is 1. If end is smaller than begin, the slice is constructed backwards.

Let Len be the length of L and let N2, N3 and N4 be the respective values of the expressions Exp2, Exp2 and Exp2 when they are present.

The slice parameters begin, end, and step are determined as follows:
  • Exp2:
    • If Exp2 is absent, then begin = 0.
    • Otherwise, if N2 >= 0 then begin = N2 else begin = N2 + Len.
  • Exp4:
    • If Exp4 is absent, then end = Len.
    • Otherwise, if N4 >= 0, then end = N4 else end = N4 + Len.
  • Exp3:
    • If Exp3 is absent, then if begin < end then step = 1 else step = -1.
    • Otherwise, if begin < end, then step = N3 - begin else step = begin - N3.
Now, the constraints 0 <= begin < Len and 0 < end < Len should hold, otherwise the exception IndexOutOfBounds is thrown.

The slice consists of the elements L[begin], L[begin+step], L[end - step]. When begin >= end, the elements are listed in reverse order.
Examples Consider the list L = [0, 10, 20, 30, 40, 50, 60, 70, 80]; as running example.

Here is a view on L that will help to correlate positive and negative indices:

i 0 1 2 3 4 5 6 7 8
L[i] 0 10 20 30 40 50 60 7080
-i -9 -8 -7 -6 -5 -4 -3 -2 -1


Some common use cases (with begin <= end):

Slice Means:
L[begin..end] elements with indices begin through end-1
L[begin..] elements with indices begin through the rest of the list
L[..end] elements with indices from the beginning through end-1
L[..] the whole list
L[-1] last element of the list
L[-2..] the last two elements of the list
L[..-2] all elements except the last two.
Let's put this into practice now.
rascal>L = [0, 10, 20, 30, 40, 50, 60, 70, 80];
list[int]: [0,10,20,30,40,50,60,70,80]
Slices with begin < end
rascal>L[1..3];
list[int]: [10,20]
rascal>L[1..];       // empty end => end of list
list[int]: [10,20,30,40,50,60,70,80]
rascal>L[..3];       // empty begin => first element of list
list[int]: [0,10,20]
rascal>L[..];        // both empty => whole list
list[int]: [0,10,20,30,40,50,60,70,80]
Slices with begin >= end
rascal>L[3..1];      // slice contains elements with indices 3 and 2 (in that order)
list[int]: [30,20]
rascal>L[3..3];      // empty slice when begin == end
list[int]: []
Slices with negative begin or end:
rascal>L[2..-2];     // equivalent to L[2..7]
list[int]: [20,30,40,50,60]
rascal>L[2..7];
list[int]: [20,30,40,50,60]
rascal>L[-4..-2];    // equivalent to L[5..7]
list[int]: [50,60]
rascal>L[5..7];
list[int]: [50,60]
Slices with an explicit second index:
rascal>L[1,3..6];
list[int]: [10,30,50]
rascal>L[5,3..];
list[int]: [50,30,10]
Explore error cases:
rascal>L[..10];
|stdin:///|(4,2,<1,4>,<1,6>): IndexOutOfBounds(10)
	at ___SCREEN_INSTANCE___(|stdin:///|(0,8,<1,0>,<1,8>))


rascal>L[1..20];
|stdin:///|(5,2,<1,5>,<1,7>): IndexOutOfBounds(20)
	at ___SCREEN_INSTANCE___(|stdin:///|(0,9,<1,0>,<1,9>))


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